Verified by Ajay Kumar
What is the least value that should be added to 1812 to make it divisible by 7, 11 and 14?
12
36
72
154
Answer: B
Solution
LCM of 7, 11 and 14 is 154. Since 1812=154×11+118, the least addition is 154-118=36.
1812 में वह न्यूनतम संख्या क्या जोड़ी जाए जिससे प्राप्त संख्या 7, 11 और 14 से विभाजित हो जाए?
12
36
72
154
उत्तर: B
हल
7, 11 और 14 का लघुत्तम समापवर्त्य 154 है। 1812=154×11+118। अतः अगली गुणज संख्या तक पहुँचने के लिए 154-118=36 जोड़ना होगा।
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