Algebra: Complete Concepts, Formulas, Shortcuts and Solved Examples | mathsbook
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Algebra: Complete Concepts, Formulas, Shortcuts and Solved Examples

Master algebra step by step with clear concepts, essential formulas, smart shortcuts, worked examples, and practice questions.

This complete guide introduces algebra from the ground up and builds towards the types of equations and expressions used in school mathematics, aptitude tests, placement assessments, and competitive examinations such as SSC, RRB and banking exams.

Learn how symbols represent numbers, how to simplify expressions, how to solve equations, and how to choose an efficient method without memorising tricks blindly.

Beginner friendlyFormula guideSolved examplesExam shortcutsPractice set
How to use this chapter: Read the concept first, study one worked example, then try the practice question before opening its solution. Algebra becomes easier when you understand why each step is valid.

1. What Is Algebra?

Algebra is a branch of mathematics that uses letters and symbols to represent numbers and relationships. Instead of working only with known numbers, algebra lets us describe a general rule or find an unknown value.

Arithmetic

Known numbers

7 + 5 = 12

All values are already given.

Algebra

An unknown value

x + 5 = 12

Find the value of the variable.

A general rule

Many possible values

a + b = b + a

The rule works for any suitable values of a and b.

Why is algebra useful?

Algebra helps you solve unknowns, model real-world situations, recognise patterns, and calculate efficiently. It supports later topics such as equations, graphs, geometry, percentages, ratios, and quantitative aptitude.

Example 1 · Understand a variable

A number increased by 8 is 21. Find the number.

1
Let the unknown number be x.
2
Translate the statement into an equation: x + 8 = 21
3
Subtract 8 from both sides: x = 21 − 8 = 13
Answer: 13

2. Basic Concepts and Vocabulary

Variable

A letter that represents a value that may be unknown or may change.

x, y, a, n

Example: In x + 4 = 10, x is the variable.

Constant

A fixed number that does not change within the expression.

7, −3, 12

Example: In 3x + 7, the constant term is 7.

Coefficient

The numerical factor multiplying a variable.

5x → coefficient is 5

In −2y, the coefficient is −2.

Term

A part of an expression separated by addition or subtraction signs.

4x + 3y − 8

The terms are 4x, 3y, and −8.

Expression, equation, and formula

TermMeaningExample
ExpressionA mathematical phrase without an equals sign.3x + 7
EquationA statement that two expressions are equal.3x + 7 = 22
FormulaA rule connecting quantities.A = l × w
IdentityAn equality true for every value in its domain.(a + b)² = a² + 2ab + b²

Like and unlike terms

Like terms have the same variable part with the same powers. Their coefficients can be combined. Unlike terms cannot be combined into one term.

Example 2 · Identify like terms

Simplify: 3x + 5 − 2x + 7.

Combine the x-terms and the constants separately:

(3x − 2x) + (5 + 7) = x + 12
Answer: x + 12

But 3x + 2y cannot be simplified to 5xy or 5x. The variables are different.

3. Fundamental Rules of Algebra

Rule 1 · Commutative property

The order can be changed for addition and multiplication.

a + b = b + a
ab = ba

Subtraction and division are not generally commutative.

Rule 2 · Associative property

Regrouping does not change a sum or a product.

(a + b) + c = a + (b + c)
(ab)c = a(bc)

Rule 3 · Distributive property

Multiply the factor outside the brackets by every term inside.

a(b + c) = ab + ac
Example 3

Simplify 4(x + 3).

4(x + 3) = 4x + 12
Answer: 4x + 12

Rule 4 · Equality stays balanced

You may add, subtract, multiply, or divide both sides of an equation by the same appropriate value. Never divide by zero.

If a = b, then a + c = b + c

When multiplying or dividing an inequality by a negative number, reverse the inequality sign.

Rule 5 · Sign rules

OperationResult
(+) × (+)Positive
(−) × (−)Positive
(+) × (−)Negative
(−) × (+)Negative

The same sign pattern applies to division when the divisor is non-zero.

4. Simplifying Algebraic Expressions

To simplify an expression, remove brackets when appropriate, apply sign rules, and combine like terms. Follow the order of operations: brackets first, powers, multiplication and division, then addition and subtraction.

Example 4 · Simplify an expression

Simplify: 3(2x − 4) + 5x − 2.

1
Expand the bracket: 6x − 12 + 5x − 2.
2
Combine like terms: (6x + 5x) + (−12 − 2).
3
Write the simplified expression: 11x − 14
Answer: 11x − 14

Removing a minus sign before brackets

A minus sign before a bracket changes the sign of every term inside.

−(a + b − c) = −a − b + c
Example 5 · Be careful with negative signs

Simplify: 8x − (3x − 5).

Change both signs inside the bracket:

8x − 3x + 5 = 5x + 5
Answer: 5x + 5

5. Important Algebraic Identities

Algebraic identities are useful for expanding expressions and recognising patterns quickly. Learn the patterns, but always check that the signs and middle terms are correct.

Identity 1

Square of a sum

(a + b)² = a² + 2ab + b²

Example: (x + 3)² = x² + 6x + 9.

Identity 2

Square of a difference

(a − b)² = a² − 2ab + b²

Example: (x − 4)² = x² − 8x + 16.

Identity 3

Difference of squares

a² − b² = (a − b)(a + b)

Example: x² − 25 = (x − 5)(x + 5).

Identity 4

Product of two binomials

(x + a)(x + b) = x² + (a + b)x + ab

Example: (x + 2)(x + 5) = x² + 7x + 10.

Identity 5

Cube of a sum

(a + b)³ = a³ + 3a²b + 3ab² + b³
Identity 6

Cube of a difference

(a − b)³ = a³ − 3a²b + 3ab² − b³
Identity 7

Sum of cubes

a³ + b³ = (a + b)(a² − ab + b²)
Identity 8

Difference of cubes

a³ − b³ = (a − b)(a² + ab + b²)
Example 6 · Use an identity to calculate quickly

Calculate 49² using an identity.

Write 49 as 50 − 1.

49² = (50 − 1)²
= 50² − 2(50)(1) + 1²
= 2500 − 100 + 1 = 2401
Answer: 2401

6. Factorisation

Factorisation means rewriting an expression as a product of simpler expressions. It reverses expansion and is especially useful for simplifying algebraic fractions and solving equations.

Method 1 · Take out a common factor

ab + ac = a(b + c)
Example 7

Factorise 6x + 12.

The highest common factor is 6.

6x + 12 = 6(x + 2)
Answer: 6(x + 2)

Method 2 · Factorise a quadratic trinomial

For x² + bx + c, look for two numbers that add to b and multiply to c.

Example 8

Factorise x² + 7x + 12.

Find two numbers whose sum is 7 and product is 12: 3 and 4.

x² + 7x + 12 = (x + 3)(x + 4)
Answer: (x + 3)(x + 4)

Method 3 · Difference of two squares

Example 9

Factorise 9x² − 16.

Recognise the squares: (3x)² − 4².

9x² − 16 = (3x − 4)(3x + 4)
Answer: (3x − 4)(3x + 4)

7. Solving Linear Equations

A linear equation in one variable has the variable to the first power. The goal is to isolate the variable while keeping both sides balanced.

Golden rule: Whatever operation you perform on one side of an equation, perform the same operation on the other side.
Example 10 · A simple equation

Solve: 3x + 7 = 25.

1
Subtract 7 from both sides: 3x = 18
2
Divide both sides by 3: x = 6
Answer: x = 6
Example 11 · Variable terms on both sides

Solve: 5x − 4 = 2x + 11.

1
Subtract 2x from both sides: 3x − 4 = 11.
2
Add 4 to both sides: 3x = 15.
3
Divide by 3: x = 5.
Answer: x = 5
Example 12 · Brackets in an equation

Solve: 2(3x − 1) = 16.

Expand, then isolate x:

6x − 2 = 16
6x = 18 → x = 3
Answer: x = 3

8. Fractions, Powers and Quadratic Equations

Algebraic fractions

To solve equations containing fractions, multiply every term on both sides by the least common denominator. Check that you do not multiply only some terms.

Example 13 · Equation with fractions

Solve: x/3 + 2 = 5.

x/3 = 3
x = 9
Answer: x = 9

Laws of exponents

RuleFormulaExample
Multiply same baseaᵐ × aⁿ = aᵐ⁺ⁿx² × x³ = x⁵
Divide same baseaᵐ ÷ aⁿ = aᵐ⁻ⁿx⁵ ÷ x² = x³, for x ≠ 0
Power of a power(aᵐ)ⁿ = aᵐⁿ(x²)³ = x⁶
Power of a product(ab)ⁿ = aⁿbⁿ(2x)² = 4x²
Zero exponenta⁰ = 1, for a ≠ 05⁰ = 1
Negative exponenta⁻ⁿ = 1/aⁿ, for a ≠ 0x⁻² = 1/x²

Quadratic equations: a first look

A quadratic equation has the form ax² + bx + c = 0, where a is not zero. Depending on the coefficients, it may be solved by factorisation, completing the square, or the quadratic formula.

x = (−b ± √(b² − 4ac)) / 2a

The expression b² − 4ac is called the discriminant. For real coefficients, it helps determine the type of roots.

Example 14 · Solve by factorisation

Solve: x² − 5x + 6 = 0.

Find two numbers that multiply to 6 and add to −5: −2 and −3.

(x − 2)(x − 3) = 0

If a product is zero, at least one factor must be zero.

x − 2 = 0 or x − 3 = 0
Answer: x = 2 or x = 3

9. Algebra Tricks and Shortcuts

Shortcuts work best when you recognise the pattern. Use them to reduce steps, not to skip the logic.

1

Combine like terms first

In 8x + 3 − 2x + 7, combine x-terms and constants:

6x + 10

This keeps the expression tidy before further operations.

2

Use identities near round numbers

For 99², write 99 = 100 − 1.

99² = 100² − 2(100) + 1 = 9801
3

Move terms carefully

Instead of saying “move it and change the sign,” think of doing the same operation to both sides.

x + 9 = 14 → x = 14 − 9 = 5
4

Factor before multiplying

Recognise x² − 49 as a difference of squares.

x² − 49 = (x − 7)(x + 7)
5

Check by substitution

If you find x = 4, substitute 4 into the original equation. This catches sign and arithmetic errors quickly.

6

Clear fractions early

For an equation with denominators 2 and 3, multiply every term by 6 to remove the fractions, while keeping the equation balanced.

7

Choose a variable for the unknown

For “three more than twice a number,” write 2x + 3—not 3x + 2.

8

Look for a common factor

In 12x + 18, take out 6.

12x + 18 = 6(2x + 3)
Shortcut rule: First identify the structure—like terms, a common factor, an identity, or a balanced equation. The structure often tells you the quickest method.

10. Turning Word Problems into Equations

Algebra becomes powerful when words are converted into mathematical statements. Define the unknown first, then translate each phrase carefully.

WordsAlgebraic form
A number increased by 7x + 7
A number decreased by 4x − 4
Twice a number2x
Three times a number, then add 53x + 5
Five less than twice a number2x − 5
One number is 8 more than anotherx = y + 8
The sum of two consecutive integersx + (x + 1)
Example 15 · Number problem

The sum of a number and twice that number is 36. Find the number.

1
Let the number be x.
2
Write the equation: x + 2x = 36
3
Simplify: 3x = 36, so x = 12.
Answer: 12
Example 16 · Consecutive integers

The sum of two consecutive integers is 41. Find the integers.

Let the first integer be x. The next integer is x + 1.

x + (x + 1) = 41
2x + 1 = 41 → 2x = 40 → x = 20
Answer: 20 and 21

11. Common Algebra Mistakes

Combining unlike terms

Incorrect: 3x + 2y = 5xy.

Correct: 3x + 2y stays as it is because x and y are unlike variables.

Squaring a sum incorrectly

Incorrect: (a + b)² = a² + b².

Correct: (a + b)² = a² + 2ab + b².

Forgetting to distribute

Incorrect: 3(x + 4) = 3x + 4.

Correct: 3(x + 4) = 3x + 12.

Sign error with brackets

Incorrect: x − (y − 2) = x − y − 2.

Correct: x − (y − 2) = x − y + 2.

Dividing by zero

Division by zero is undefined. Check denominators before simplifying algebraic fractions.

Not checking the answer

Substitute the solution into the original equation. If both sides are equal, the solution passes the check.

12. How to Prepare for Algebra

Build confidence in layers. Do not rush to advanced identities before you can simplify expressions and solve one-step equations accurately.

DayFocusPractice target
1Variables, terms and expressions15 questions
2Like terms, brackets and sign rules15 questions
3Identities and expansion12 questions
4Factorisation12 questions
5Linear equations and fractions15 questions
6Word problems and exponents15 questions
7Mixed revision and a timed quiz20 questions

A practical study routine

  1. Read the concept and copy the formula in your own words.
  2. Study one worked example, then cover the solution and redo it.
  3. Attempt 10–15 questions without looking at the answer key.
  4. Record mistakes by type: concept, sign, equation setup, or arithmetic.
  5. Reattempt incorrect questions the next day.
Exam preparation tip: For SSC, RRB and banking aptitude, prioritise simplification, identities, factorisation, linear equations and algebraic word problems according to the syllabus of your target exam. For broader mathematics study, continue to quadratics, inequalities, graphs and functions.

13. Practice Questions

Try each question before opening the solution. The questions move from basic operations to equations, identities and factorisation.

Q1 · Basic Simplify: 7x + 3x − 4.

Solution: Combine like terms: 7x + 3x = 10x.

Answer: 10x − 4

Trick: Combine variable terms separately from constants.

Q2 · Basic If x + 9 = 23, find x.

Subtract 9 from both sides: x = 23 − 9.

Answer: x = 14

Trick: Undo addition with subtraction.

Q3 · Basic Solve: 5x = 45.

Divide both sides by 5.

Answer: x = 9

Trick: Undo multiplication with division.

Q4 · Intermediate Simplify: 3(2x + 5) − 4x.

Expand: 6x + 15 − 4x. Combine like terms.

Answer: 2x + 15

Trick: Expand brackets before combining terms.

Q5 · Intermediate Solve: 4x − 7 = 21.

Add 7: 4x = 28. Divide by 4.

Answer: x = 7
Q6 · Intermediate Solve: 3x + 4 = x + 18.

Subtract x: 2x + 4 = 18. Subtract 4: 2x = 14. Therefore x = 7.

Answer: x = 7
Q7 · Identity Expand: (x + 5)².

Use (a + b)² = a² + 2ab + b².

Answer: x² + 10x + 25

Trick: The middle term is twice the product of the two parts.

Q8 · Identity Factorise: x² − 36.

This is a difference of squares: x² − 6².

Answer: (x − 6)(x + 6)
Q9 · Factorisation Factorise: x² + 9x + 20.

Find two numbers that add to 9 and multiply to 20: 4 and 5.

Answer: (x + 4)(x + 5)
Q10 · Intermediate Solve: 2(x − 3) = 18.

Divide both sides by 2: x − 3 = 9. Add 3.

Answer: x = 12
Q11 · Fractions Solve: x/4 + 3 = 8.

Subtract 3: x/4 = 5. Multiply by 4.

Answer: x = 20
Q12 · Exponents Simplify: x³ × x⁴.

For the same base, add the exponents: 3 + 4 = 7.

Answer: x⁷
Q13 · Word problem Five more than twice a number is 29. Find the number.

Let the number be x. Write 2x + 5 = 29. Then 2x = 24, so x = 12.

Answer: 12
Q14 · Word problem The sum of two consecutive integers is 73. Find them.

Let them be x and x + 1. Then 2x + 1 = 73, so 2x = 72 and x = 36.

Answer: 36 and 37
Q15 · Quadratic Solve: x² − 7x + 12 = 0.

Factorise: (x − 3)(x − 4) = 0.

Answer: x = 3 or x = 4
Q16 · Intermediate Simplify: 5a − 2b + 3a + 7b.

Combine a-terms: 5a + 3a = 8a. Combine b-terms: −2b + 7b = 5b.

Answer: 8a + 5b
Q17 · Factorisation Factorise: 6x² + 9x.

Take out the common factor 3x.

Answer: 3x(2x + 3)
Q18 · Equation Solve: 7 − 2x = 15.

Subtract 7: −2x = 8. Divide by −2.

Answer: x = −4

Check: 7 − 2(−4) = 15.

Q19 · Identity Evaluate 101² using an identity.

Write 101 = 100 + 1.

101² = 100² + 2(100)(1) + 1²
Answer: 10201
Q20 · Mixed If 2x + 3 = 17, find 3x − 1.

First solve: 2x = 14, so x = 7. Substitute into the requested expression: 3(7) − 1 = 20.

Answer: 20

14. Frequently Asked Questions

What is the easiest way to learn algebra?

Start with variables, coefficients, like terms, and the distributive property. Then move to linear equations, identities, factorisation, and word problems.

Which algebra topics should I prepare for competitive exams?

Study the topics listed in your target exam syllabus. Common foundations include simplification, algebraic identities, factorisation, linear equations, exponents, and translating word problems into equations.

How can I solve algebra questions faster?

Recognise patterns, combine like terms early, use identities where appropriate, factorise before expanding when useful, and check answers by substitution.

Do I need to memorise every algebraic identity?

Learn the most common identities and understand how they are derived. Understanding the pattern makes it easier to remember and apply them correctly.

Is algebra useful outside competitive examinations?

Yes. Algebra is a foundational part of mathematics used in science, technology, finance, data analysis, engineering, and everyday problem-solving.

Final Summary

Algebra is easier when you understand the meaning behind each symbol and keep equations balanced. Learn to simplify expressions, apply identities, factorise carefully, and solve equations one step at a time.

Remember these principles: combine only like terms, distribute factors across every term in brackets, use identities with the correct signs, isolate variables using balanced operations, and check solutions in the original problem.

Keep learning with mathsbook — strengthen your concepts, improve your accuracy, and solve mathematics with confidence.

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